PSLE
Gwen took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 8.6 km to reach Gwen's home. How much was her taxi fare?

Taxi Fare
First km	$2.20
Every additional 400 m or less	$0.26
Every 45 seconds waiting or less	$0.30

Amount to pay for the first 1 km = $2.20

Remaining distance to pay for
= 8.6 - 1
= 7.6 km

1 km = 1000 m
7.6 km = 7.6 x 1000 = 7600 m

Sets of additional 400 m
= 7600 ÷ 400
= 19 r 0

Amount to pay for remaining 7.6 km
= 19 x 0.26
= $4.94

1 min = 60 s
2 min = 2 x 60 = 120 s

Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30

Sets of 45 seconds of waiting or less
= 2 + 1
= 3

Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.30
= $0.90

Gwen's taxi fare
= 2.20 + 4.94 + 0.90
= $8.04

Answer(s): $8.04