PSLE Opal took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 9.4 km to reach Opal's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.70 |
Every additional 300 m or less |
$0.28 |
Every 45 seconds waiting or less |
$0.30 |
Amount to pay for the first 1 km = $3.70
Remaining distance to pay for
= 9.4 - 1
= 8.4 km
1 km = 1000 m
8.4 km = 8.4 x 1000 = 8400 m
Sets of additional 300 m
= 8400 ÷ 300
= 28 r 0
Amount to pay for remaining 8.4 km
= 28 x 0.28
= $7.84
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30
Sets of 45 seconds of waiting or less
= 2 + 1
= 3
Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.30
= $0.90
Opal's taxi fare
= 3.70 + 7.84 + 0.90
= $12.44
Answer(s): $12.44