PSLE Opal took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 8.7 km to reach Opal's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.90 |
Every additional 500 m or less |
$0.23 |
Every 30 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $3.90
Remaining distance to pay for
= 8.7 - 1
= 7.7 km
1 km = 1000 m
7.7 km = 7.7 x 1000 = 7700 m
Sets of additional 500 m
= 7700 ÷ 500
= 15 r 200
Sets of additional 500 m or less
= 15 + 1
= 16
Amount to pay for remaining 7.7 km
= 16 x 0.23
= $3.68
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 30 seconds of waiting
= 120 ÷ 30
= 4 r 0
Amount to pay for sets of 30 seconds of waiting or less
= 4 x 0.40
= $1.60
Opal's taxi fare
= 3.90 + 3.68 + 1.60
= $9.18
Answer(s): $9.18