PSLE Penelope took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 7.1 km to reach Penelope's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.70 |
Every additional 400 m or less |
$0.23 |
Every 35 seconds waiting or less |
$0.30 |
Amount to pay for the first 1 km = $3.70
Remaining distance to pay for
= 7.1 - 1
= 6.1 km
1 km = 1000 m
6.1 km = 6.1 x 1000 = 6100 m
Sets of additional 400 m
= 6100 ÷ 400
= 15 r 100
Sets of additional 400 m or less
= 15 + 1
= 16
Amount to pay for remaining 6.1 km
= 16 x 0.23
= $3.68
1 min = 60 s
3 min = 3 x 60 = 180 s
Sets of 35 seconds of waiting
= 180 ÷ 35
= 5 r 5
Sets of 35 seconds of waiting or less
= 5 + 1
= 6
Amount to pay for sets of 35 seconds of waiting or less
= 6 x 0.30
= $1.80
Penelope's taxi fare
= 3.70 + 3.68 + 1.80
= $9.18
Answer(s): $9.18