PSLE Nora took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 6.4 km to reach Nora's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.60 |
Every additional 300 m or less |
$0.32 |
Every 35 seconds waiting or less |
$0.30 |
Amount to pay for the first 1 km = $2.60
Remaining distance to pay for
= 6.4 - 1
= 5.4 km
1 km = 1000 m
5.4 km = 5.4 x 1000 = 5400 m
Sets of additional 300 m
= 5400 ÷ 300
= 18 r 0
Amount to pay for remaining 5.4 km
= 18 x 0.32
= $5.76
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 35 seconds of waiting
= 120 ÷ 35
= 3 r 15
Sets of 35 seconds of waiting or less
= 3 + 1
= 4
Amount to pay for sets of 35 seconds of waiting or less
= 4 x 0.30
= $1.20
Nora's taxi fare
= 2.60 + 5.76 + 1.20
= $9.56
Answer(s): $9.56