PSLE
Betty took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 4.9 km to reach Betty's home. How much was her taxi fare?

Taxi Fare
First km	$3.30
Every additional 300 m or less	$0.29
Every 40 seconds waiting or less	$0.40

Amount to pay for the first 1 km = $3.30

Remaining distance to pay for
= 4.9 - 1
= 3.9 km

1 km = 1000 m
3.9 km = 3.9 x 1000 = 3900 m

Sets of additional 300 m
= 3900 ÷ 300
= 13 r 0

Amount to pay for remaining 3.9 km
= 13 x 0.29
= $3.77

1 min = 60 s
3 min = 3 x 60 = 180 s

Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20

Sets of 40 seconds of waiting or less
= 4 + 1
= 5

Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.40
= $2.00

Betty's taxi fare
= 3.30 + 3.77 + 2.00
= $9.07

Answer(s): $9.07