PSLE
Penelope took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 5.8 km to reach Penelope's home. How much was her taxi fare?

Taxi Fare
First km	$2.70
Every additional 500 m or less	$0.23
Every 35 seconds waiting or less	$0.40

Amount to pay for the first 1 km = $2.70

Remaining distance to pay for
= 5.8 - 1
= 4.8 km

1 km = 1000 m
4.8 km = 4.8 x 1000 = 4800 m

Sets of additional 500 m
= 4800 ÷ 500
= 9 r 300

Sets of additional 500 m or less
= 9 + 1
= 10

Amount to pay for remaining 4.8 km
= 10 x 0.23
= $2.30

1 min = 60 s
2 min = 2 x 60 = 120 s

Sets of 35 seconds of waiting
= 120 ÷ 35
= 3 r 15

Sets of 35 seconds of waiting or less
= 3 + 1
= 4

Amount to pay for sets of 35 seconds of waiting or less
= 4 x 0.40
= $1.60

Penelope's taxi fare
= 2.70 + 2.30 + 1.60
= $6.60

Answer(s): $6.60