PSLE
Esther took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 5.1 km to reach Esther's home. How much was her taxi fare?

Taxi Fare
First km	$2.20
Every additional 400 m or less	$0.41
Every 40 seconds waiting or less	$0.30

Amount to pay for the first 1 km = $2.20

Remaining distance to pay for
= 5.1 - 1
= 4.1 km

1 km = 1000 m
4.1 km = 4.1 x 1000 = 4100 m

Sets of additional 400 m
= 4100 ÷ 400
= 10 r 100

Sets of additional 400 m or less
= 10 + 1
= 11

Amount to pay for remaining 4.1 km
= 11 x 0.41
= $4.51

1 min = 60 s
3 min = 3 x 60 = 180 s

Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20

Sets of 40 seconds of waiting or less
= 4 + 1
= 5

Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.30
= $1.50

Esther's taxi fare
= 2.20 + 4.51 + 1.50
= $8.21

Answer(s): $8.21