PSLE
Hazel took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 6.5 km to reach Hazel's home. How much was her taxi fare?

Taxi Fare
First km	$2.10
Every additional 500 m or less	$0.41
Every 40 seconds waiting or less	$0.40

Amount to pay for the first 1 km = $2.10

Remaining distance to pay for
= 6.5 - 1
= 5.5 km

1 km = 1000 m
5.5 km = 5.5 x 1000 = 5500 m

Sets of additional 500 m
= 5500 ÷ 500
= 11 r 0

Amount to pay for remaining 5.5 km
= 11 x 0.41
= $4.51

1 min = 60 s
3 min = 3 x 60 = 180 s

Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20

Sets of 40 seconds of waiting or less
= 4 + 1
= 5

Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.40
= $2.00

Hazel's taxi fare
= 2.10 + 4.51 + 2.00
= $8.61

Answer(s): $8.61