PSLE Roshel took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 5.9 km to reach Roshel's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.10 |
Every additional 400 m or less |
$0.34 |
Every 30 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $2.10
Remaining distance to pay for
= 5.9 - 1
= 4.9 km
1 km = 1000 m
4.9 km = 4.9 x 1000 = 4900 m
Sets of additional 400 m
= 4900 ÷ 400
= 12 r 100
Sets of additional 400 m or less
= 12 + 1
= 13
Amount to pay for remaining 4.9 km
= 13 x 0.34
= $4.42
1 min = 60 s
3 min = 3 x 60 = 180 s
Sets of 30 seconds of waiting
= 180 ÷ 30
= 6 r 0
Amount to pay for sets of 30 seconds of waiting or less
= 6 x 0.40
= $2.40
Roshel's taxi fare
= 2.10 + 4.42 + 2.40
= $8.92
Answer(s): $8.92