PSLE Jane took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 7.2 km to reach Jane's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.10 |
Every additional 400 m or less |
$0.28 |
Every 40 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $3.10
Remaining distance to pay for
= 7.2 - 1
= 6.2 km
1 km = 1000 m
6.2 km = 6.2 x 1000 = 6200 m
Sets of additional 400 m
= 6200 ÷ 400
= 15 r 200
Sets of additional 400 m or less
= 15 + 1
= 16
Amount to pay for remaining 6.2 km
= 16 x 0.28
= $4.48
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 40 seconds of waiting
= 120 ÷ 40
= 3 r 0
Amount to pay for sets of 40 seconds of waiting or less
= 3 x 0.40
= $1.20
Jane's taxi fare
= 3.10 + 4.48 + 1.20
= $8.78
Answer(s): $8.78