PSLE Jade took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 6.1 km to reach Jade's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.80 |
Every additional 300 m or less |
$0.21 |
Every 35 seconds waiting or less |
$0.20 |
Amount to pay for the first 1 km = $2.80
Remaining distance to pay for
= 6.1 - 1
= 5.1 km
1 km = 1000 m
5.1 km = 5.1 x 1000 = 5100 m
Sets of additional 300 m
= 5100 ÷ 300
= 17 r 0
Amount to pay for remaining 5.1 km
= 17 x 0.21
= $3.57
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 35 seconds of waiting
= 120 ÷ 35
= 3 r 15
Sets of 35 seconds of waiting or less
= 3 + 1
= 4
Amount to pay for sets of 35 seconds of waiting or less
= 4 x 0.20
= $0.80
Jade's taxi fare
= 2.80 + 3.57 + 0.80
= $7.17
Answer(s): $7.17