PSLE Xylia took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 5.1 km to reach Xylia's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.60 |
Every additional 300 m or less |
$0.31 |
Every 40 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $2.60
Remaining distance to pay for
= 5.1 - 1
= 4.1 km
1 km = 1000 m
4.1 km = 4.1 x 1000 = 4100 m
Sets of additional 300 m
= 4100 ÷ 300
= 13 r 200
Sets of additional 300 m or less
= 13 + 1
= 14
Amount to pay for remaining 4.1 km
= 14 x 0.31
= $4.34
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 40 seconds of waiting
= 120 ÷ 40
= 3 r 0
Amount to pay for sets of 40 seconds of waiting or less
= 3 x 0.40
= $1.20
Xylia's taxi fare
= 2.60 + 4.34 + 1.20
= $8.14
Answer(s): $8.14