PSLE Opal took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 4.5 km to reach Opal's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.70 |
Every additional 500 m or less |
$0.36 |
Every 40 seconds waiting or less |
$0.30 |
Amount to pay for the first 1 km = $2.70
Remaining distance to pay for
= 4.5 - 1
= 3.5 km
1 km = 1000 m
3.5 km = 3.5 x 1000 = 3500 m
Sets of additional 500 m
= 3500 ÷ 500
= 7 r 0
Amount to pay for remaining 3.5 km
= 7 x 0.36
= $2.52
1 min = 60 s
3 min = 3 x 60 = 180 s
Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20
Sets of 40 seconds of waiting or less
= 4 + 1
= 5
Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.30
= $1.50
Opal's taxi fare
= 2.70 + 2.52 + 1.50
= $6.72
Answer(s): $6.72