PSLE
Opal took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 8.8 km to reach Opal's home. How much was her taxi fare?

Taxi Fare
First km	$2.70
Every additional 500 m or less	$0.21
Every 45 seconds waiting or less	$0.20

Amount to pay for the first 1 km = $2.70

Remaining distance to pay for
= 8.8 - 1
= 7.8 km

1 km = 1000 m
7.8 km = 7.8 x 1000 = 7800 m

Sets of additional 500 m
= 7800 ÷ 500
= 15 r 300

Sets of additional 500 m or less
= 15 + 1
= 16

Amount to pay for remaining 7.8 km
= 16 x 0.21
= $3.36

1 min = 60 s
2 min = 2 x 60 = 120 s

Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30

Sets of 45 seconds of waiting or less
= 2 + 1
= 3

Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.20
= $0.60

Opal's taxi fare
= 2.70 + 3.36 + 0.60
= $6.66

Answer(s): $6.66