PSLE Shannon took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 5.6 km to reach Shannon's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.40 |
Every additional 300 m or less |
$0.29 |
Every 45 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $3.40
Remaining distance to pay for
= 5.6 - 1
= 4.6 km
1 km = 1000 m
4.6 km = 4.6 x 1000 = 4600 m
Sets of additional 300 m
= 4600 ÷ 300
= 15 r 100
Sets of additional 300 m or less
= 15 + 1
= 16
Amount to pay for remaining 4.6 km
= 16 x 0.29
= $4.64
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30
Sets of 45 seconds of waiting or less
= 2 + 1
= 3
Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.40
= $1.20
Shannon's taxi fare
= 3.40 + 4.64 + 1.20
= $9.24
Answer(s): $9.24