PSLE Usha took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 4.2 km to reach Usha's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.40 |
Every additional 500 m or less |
$0.23 |
Every 35 seconds waiting or less |
$0.30 |
Amount to pay for the first 1 km = $3.40
Remaining distance to pay for
= 4.2 - 1
= 3.2 km
1 km = 1000 m
3.2 km = 3.2 x 1000 = 3200 m
Sets of additional 500 m
= 3200 ÷ 500
= 6 r 200
Sets of additional 500 m or less
= 6 + 1
= 7
Amount to pay for remaining 3.2 km
= 7 x 0.23
= $1.61
1 min = 60 s
3 min = 3 x 60 = 180 s
Sets of 35 seconds of waiting
= 180 ÷ 35
= 5 r 5
Sets of 35 seconds of waiting or less
= 5 + 1
= 6
Amount to pay for sets of 35 seconds of waiting or less
= 6 x 0.30
= $1.80
Usha's taxi fare
= 3.40 + 1.61 + 1.80
= $6.81
Answer(s): $6.81