PSLE Linda took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 6.6 km to reach Linda's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.80 |
Every additional 400 m or less |
$0.41 |
Every 45 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $2.80
Remaining distance to pay for
= 6.6 - 1
= 5.6 km
1 km = 1000 m
5.6 km = 5.6 x 1000 = 5600 m
Sets of additional 400 m
= 5600 ÷ 400
= 14 r 0
Amount to pay for remaining 5.6 km
= 14 x 0.41
= $5.74
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30
Sets of 45 seconds of waiting or less
= 2 + 1
= 3
Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.40
= $1.20
Linda's taxi fare
= 2.80 + 5.74 + 1.20
= $9.74
Answer(s): $9.74