PSLE Lynn took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 6.8 km to reach Lynn's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.70 |
Every additional 500 m or less |
$0.41 |
Every 45 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $3.70
Remaining distance to pay for
= 6.8 - 1
= 5.8 km
1 km = 1000 m
5.8 km = 5.8 x 1000 = 5800 m
Sets of additional 500 m
= 5800 ÷ 500
= 11 r 300
Sets of additional 500 m or less
= 11 + 1
= 12
Amount to pay for remaining 5.8 km
= 12 x 0.41
= $4.92
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30
Sets of 45 seconds of waiting or less
= 2 + 1
= 3
Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.40
= $1.20
Lynn's taxi fare
= 3.70 + 4.92 + 1.20
= $9.82
Answer(s): $9.82