PSLE Jade took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 9.2 km to reach Jade's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.40 |
Every additional 400 m or less |
$0.27 |
Every 35 seconds waiting or less |
$0.20 |
Amount to pay for the first 1 km = $2.40
Remaining distance to pay for
= 9.2 - 1
= 8.2 km
1 km = 1000 m
8.2 km = 8.2 x 1000 = 8200 m
Sets of additional 400 m
= 8200 ÷ 400
= 20 r 200
Sets of additional 400 m or less
= 20 + 1
= 21
Amount to pay for remaining 8.2 km
= 21 x 0.27
= $5.67
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 35 seconds of waiting
= 120 ÷ 35
= 3 r 15
Sets of 35 seconds of waiting or less
= 3 + 1
= 4
Amount to pay for sets of 35 seconds of waiting or less
= 4 x 0.20
= $0.80
Jade's taxi fare
= 2.40 + 5.67 + 0.80
= $8.87
Answer(s): $8.87