PSLE
Shannon took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 6.8 km to reach Shannon's home. How much was her taxi fare?

Taxi Fare
First km	$2.70
Every additional 500 m or less	$0.35
Every 35 seconds waiting or less	$0.40

Amount to pay for the first 1 km = $2.70

Remaining distance to pay for
= 6.8 - 1
= 5.8 km

1 km = 1000 m
5.8 km = 5.8 x 1000 = 5800 m

Sets of additional 500 m
= 5800 ÷ 500
= 11 r 300

Sets of additional 500 m or less
= 11 + 1
= 12

Amount to pay for remaining 5.8 km
= 12 x 0.35
= $4.20

1 min = 60 s
3 min = 3 x 60 = 180 s

Sets of 35 seconds of waiting
= 180 ÷ 35
= 5 r 5

Sets of 35 seconds of waiting or less
= 5 + 1
= 6

Amount to pay for sets of 35 seconds of waiting or less
= 6 x 0.40
= $2.40

Shannon's taxi fare
= 2.70 + 4.20 + 2.40
= $9.30

Answer(s): $9.30