PSLE Roshel took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 8.9 km to reach Roshel's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.10 |
Every additional 400 m or less |
$0.32 |
Every 40 seconds waiting or less |
$0.20 |
Amount to pay for the first 1 km = $3.10
Remaining distance to pay for
= 8.9 - 1
= 7.9 km
1 km = 1000 m
7.9 km = 7.9 x 1000 = 7900 m
Sets of additional 400 m
= 7900 ÷ 400
= 19 r 300
Sets of additional 400 m or less
= 19 + 1
= 20
Amount to pay for remaining 7.9 km
= 20 x 0.32
= $6.40
1 min = 60 s
3 min = 3 x 60 = 180 s
Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20
Sets of 40 seconds of waiting or less
= 4 + 1
= 5
Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.20
= $1.00
Roshel's taxi fare
= 3.10 + 6.40 + 1.00
= $10.50
Answer(s): $10.50