PSLE
Jane took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 9.3 km to reach Jane's home. How much was her taxi fare?

Taxi Fare
First km	$2.40
Every additional 400 m or less	$0.39
Every 30 seconds waiting or less	$0.40

Amount to pay for the first 1 km = $2.40

Remaining distance to pay for
= 9.3 - 1
= 8.3 km

1 km = 1000 m
8.3 km = 8.3 x 1000 = 8300 m

Sets of additional 400 m
= 8300 ÷ 400
= 20 r 300

Sets of additional 400 m or less
= 20 + 1
= 21

Amount to pay for remaining 8.3 km
= 21 x 0.39
= $8.19

1 min = 60 s
2 min = 2 x 60 = 120 s

Sets of 30 seconds of waiting
= 120 ÷ 30
= 4 r 0

Amount to pay for sets of 30 seconds of waiting or less
= 4 x 0.40
= $1.60

Jane's taxi fare
= 2.40 + 8.19 + 1.60
= $12.19

Answer(s): $12.19