PSLE
Pamela took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 6.4 km to reach Pamela's home. How much was her taxi fare?

Taxi Fare
First km	$2.80
Every additional 500 m or less	$0.31
Every 40 seconds waiting or less	$0.20

Amount to pay for the first 1 km = $2.80

Remaining distance to pay for
= 6.4 - 1
= 5.4 km

1 km = 1000 m
5.4 km = 5.4 x 1000 = 5400 m

Sets of additional 500 m
= 5400 ÷ 500
= 10 r 400

Sets of additional 500 m or less
= 10 + 1
= 11

Amount to pay for remaining 5.4 km
= 11 x 0.31
= $3.41

1 min = 60 s
3 min = 3 x 60 = 180 s

Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20

Sets of 40 seconds of waiting or less
= 4 + 1
= 5

Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.20
= $1.00

Pamela's taxi fare
= 2.80 + 3.41 + 1.00
= $7.21

Answer(s): $7.21