PSLE
Gem took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 7.8 km to reach Gem's home. How much was her taxi fare?

Taxi Fare
First km	$2.30
Every additional 400 m or less	$0.41
Every 40 seconds waiting or less	$0.20

Amount to pay for the first 1 km = $2.30

Remaining distance to pay for
= 7.8 - 1
= 6.8 km

1 km = 1000 m
6.8 km = 6.8 x 1000 = 6800 m

Sets of additional 400 m
= 6800 ÷ 400
= 17 r 0

Amount to pay for remaining 6.8 km
= 17 x 0.41
= $6.97

1 min = 60 s
3 min = 3 x 60 = 180 s

Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20

Sets of 40 seconds of waiting or less
= 4 + 1
= 5

Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.20
= $1.00

Gem's taxi fare
= 2.30 + 6.97 + 1.00
= $10.27

Answer(s): $10.27