PSLE Abi took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 6.9 km to reach Abi's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.30 |
Every additional 400 m or less |
$0.36 |
Every 40 seconds waiting or less |
$0.30 |
Amount to pay for the first 1 km = $2.30
Remaining distance to pay for
= 6.9 - 1
= 5.9 km
1 km = 1000 m
5.9 km = 5.9 x 1000 = 5900 m
Sets of additional 400 m
= 5900 ÷ 400
= 14 r 300
Sets of additional 400 m or less
= 14 + 1
= 15
Amount to pay for remaining 5.9 km
= 15 x 0.36
= $5.40
1 min = 60 s
3 min = 3 x 60 = 180 s
Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20
Sets of 40 seconds of waiting or less
= 4 + 1
= 5
Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.30
= $1.50
Abi's taxi fare
= 2.30 + 5.40 + 1.50
= $9.20
Answer(s): $9.20