PSLE
Min took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 4.8 km to reach Min's home. How much was her taxi fare?

Taxi Fare
First km	$2.80
Every additional 500 m or less	$0.21
Every 40 seconds waiting or less	$0.30

Amount to pay for the first 1 km = $2.80

Remaining distance to pay for
= 4.8 - 1
= 3.8 km

1 km = 1000 m
3.8 km = 3.8 x 1000 = 3800 m

Sets of additional 500 m
= 3800 ÷ 500
= 7 r 300

Sets of additional 500 m or less
= 7 + 1
= 8

Amount to pay for remaining 3.8 km
= 8 x 0.21
= $1.68

1 min = 60 s
2 min = 2 x 60 = 120 s

Sets of 40 seconds of waiting
= 120 ÷ 40
= 3 r 0

Amount to pay for sets of 40 seconds of waiting or less
= 3 x 0.30
= $0.90

Min's taxi fare
= 2.80 + 1.68 + 0.90
= $5.38

Answer(s): $5.38