PSLE Dana took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 6.6 km to reach Dana's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.50 |
Every additional 500 m or less |
$0.23 |
Every 30 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $3.50
Remaining distance to pay for
= 6.6 - 1
= 5.6 km
1 km = 1000 m
5.6 km = 5.6 x 1000 = 5600 m
Sets of additional 500 m
= 5600 ÷ 500
= 11 r 100
Sets of additional 500 m or less
= 11 + 1
= 12
Amount to pay for remaining 5.6 km
= 12 x 0.23
= $2.76
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 30 seconds of waiting
= 120 ÷ 30
= 4 r 0
Amount to pay for sets of 30 seconds of waiting or less
= 4 x 0.40
= $1.60
Dana's taxi fare
= 3.50 + 2.76 + 1.60
= $7.86
Answer(s): $7.86