PSLE Gillian took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 5.5 km to reach Gillian's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.80 |
Every additional 300 m or less |
$0.32 |
Every 40 seconds waiting or less |
$0.20 |
Amount to pay for the first 1 km = $2.80
Remaining distance to pay for
= 5.5 - 1
= 4.5 km
1 km = 1000 m
4.5 km = 4.5 x 1000 = 4500 m
Sets of additional 300 m
= 4500 ÷ 300
= 15 r 0
Amount to pay for remaining 4.5 km
= 15 x 0.32
= $4.80
1 min = 60 s
3 min = 3 x 60 = 180 s
Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20
Sets of 40 seconds of waiting or less
= 4 + 1
= 5
Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.20
= $1.00
Gillian's taxi fare
= 2.80 + 4.80 + 1.00
= $8.60
Answer(s): $8.60