PSLE Roshel took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 7.4 km to reach Roshel's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.90 |
Every additional 400 m or less |
$0.35 |
Every 40 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $2.90
Remaining distance to pay for
= 7.4 - 1
= 6.4 km
1 km = 1000 m
6.4 km = 6.4 x 1000 = 6400 m
Sets of additional 400 m
= 6400 ÷ 400
= 16 r 0
Amount to pay for remaining 6.4 km
= 16 x 0.35
= $5.60
1 min = 60 s
3 min = 3 x 60 = 180 s
Sets of 40 seconds of waiting
= 180 ÷ 40
= 4 r 20
Sets of 40 seconds of waiting or less
= 4 + 1
= 5
Amount to pay for sets of 40 seconds of waiting or less
= 5 x 0.40
= $2.00
Roshel's taxi fare
= 2.90 + 5.60 + 2.00
= $10.50
Answer(s): $10.50