PSLE Kimberly took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 9.9 km to reach Kimberly's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.10 |
Every additional 500 m or less |
$0.21 |
Every 45 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $3.10
Remaining distance to pay for
= 9.9 - 1
= 8.9 km
1 km = 1000 m
8.9 km = 8.9 x 1000 = 8900 m
Sets of additional 500 m
= 8900 ÷ 500
= 17 r 400
Sets of additional 500 m or less
= 17 + 1
= 18
Amount to pay for remaining 8.9 km
= 18 x 0.21
= $3.78
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30
Sets of 45 seconds of waiting or less
= 2 + 1
= 3
Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.40
= $1.20
Kimberly's taxi fare
= 3.10 + 3.78 + 1.20
= $8.08
Answer(s): $8.08