PSLE Jaslyn took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 6.2 km to reach Jaslyn's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.50 |
Every additional 500 m or less |
$0.35 |
Every 45 seconds waiting or less |
$0.20 |
Amount to pay for the first 1 km = $2.50
Remaining distance to pay for
= 6.2 - 1
= 5.2 km
1 km = 1000 m
5.2 km = 5.2 x 1000 = 5200 m
Sets of additional 500 m
= 5200 ÷ 500
= 10 r 200
Sets of additional 500 m or less
= 10 + 1
= 11
Amount to pay for remaining 5.2 km
= 11 x 0.35
= $3.85
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30
Sets of 45 seconds of waiting or less
= 2 + 1
= 3
Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.20
= $0.60
Jaslyn's taxi fare
= 2.50 + 3.85 + 0.60
= $6.95
Answer(s): $6.95