PSLE Jaslyn took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 5.1 km to reach Jaslyn's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$3.10 |
Every additional 500 m or less |
$0.44 |
Every 45 seconds waiting or less |
$0.40 |
Amount to pay for the first 1 km = $3.10
Remaining distance to pay for
= 5.1 - 1
= 4.1 km
1 km = 1000 m
4.1 km = 4.1 x 1000 = 4100 m
Sets of additional 500 m
= 4100 ÷ 500
= 8 r 100
Sets of additional 500 m or less
= 8 + 1
= 9
Amount to pay for remaining 4.1 km
= 9 x 0.44
= $3.96
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30
Sets of 45 seconds of waiting or less
= 2 + 1
= 3
Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.40
= $1.20
Jaslyn's taxi fare
= 3.10 + 3.96 + 1.20
= $8.26
Answer(s): $8.26