PSLE A player has to play a total of five games in Round 2 of a competition. The scores for Pierre's first four games are shown. Pierre will qualify for Round 3 if his average score for four of the five games is 60 or more. What is the lowest score Pierre must get in the 5
th game to qualify for Round 3?
Round 2 |
Game |
Score |
1st |
51 |
2nd |
56 |
3rd |
57 |
4th |
59 |
5th |
? |
Lowest total score for four games to qualify
= 4 x 60
= 240
To get the lowest score in the fifth game to qualify for Round 3, we need to exclude the lowest score (51) at the 1st game in Round 2 so that the rest of the four games can be as high as possible to qualify for Round 3.
Hence, the 2nd, the 3rd, the 4th, and the 5th games must score a total of 240.
Score in the 5th game
= 240 - 56 - 57 - 59
= 68
Answer(s): 68