PSLE A player has to play a total of five games in Round 4 of a competition. The scores for Daniel's first four games are shown. Daniel will qualify for Round 5 if his average score for four of the five games is 50 or more. What is the lowest score Daniel must get in the 5
th game to qualify for Round 5?
Round 4 |
Game |
Score |
1st |
48 |
2nd |
45 |
3rd |
38 |
4th |
49 |
5th |
? |
Lowest total score for four games to qualify
= 4 x 50
= 200
To get the lowest score in the fifth game to qualify for Round 5, we need to exclude the lowest score (38) at the 3rd game in Round 4 so that the rest of the four games can be as high as possible to qualify for Round 5.
Hence, the 1st, the 2nd, the 4th, and the 5th games must score a total of 200.
Score in the 5th game
= 200 - 48 - 45 - 49
= 58
Answer(s): 58