PSLE
A rectangular block D was cut along the dotted line into two smaller rectangular blocks of equal height, E and F, as shown. The volume of F is 3910 cm³ more than that of E.

1. What is the height of each block? 
2. Howard packed 8 of block F such that they fit exactly into a box with a square base. The box has the same height as F. At most, how many of block E can be packed into such a box? 

(a)
Base area of Block E
= 11 x 20
= 220 cm²

Base area of Block F
= 30 x 20
= 450 cm²

Base area of Block F more than Block E
= 450 - 220
= 230 cm²

Height of each block
= 3910 ÷ 230
= 17 cm

(b)
Base area of the box
= 8 x 450
= 3600 cm³

Length of the box
= √3600
= 60 cm

Number of Block E along the length of the box
= 60 ÷ 11
= 5 r 5 

Number of Block E along the breadth of the box
= 60 ÷ 20
= 3

Number of Block E to pack into the box at most
= 5 x 3
= 15

Answer(s): (a) 17 cm; (b) 15