PSLE One copier took 60 minutes while another took 120 minutes to print the same number of leaflets. The faster copier printed 10 more leaflets per minute than the slower one.
- The slower copier completed the job at 2.30 p.m. At what time was the printing started?
- What was the total number of leaflets printed by the two copiers?
(a)
120 min before 2.30 p.m. = 12.30 p.m.
Time that the printing started for the slower copier = 12.30 p.m.
(b)
Extra leaflets that the faster copier printed in 60 min
= 60 x 10
= 600
Difference in the time needed to print the leaflets
= 120 - 60
= 60 min
Speed of the slower copier
= 600 ÷ 60
= 10
Number of leaflets printed by the slower copier
= 120 x 10
= 1200
Both copiers printed the same number of leaflets.
Number of leaflets printed by the 2 copiers
= 2 x 1200
= 2400
Answer(s): (a) 12.30 p.m.; (b) 2400