PSLE One copier took 50 minutes while another took 80 minutes to print the same number of leaflets. The faster copier printed 6 more leaflets per minute than the slower one.
- The slower copier completed the job at 1.37 p.m. At what time was the printing started?
- What was the total number of leaflets printed by the two copiers?
(a)
80 min before 1.37 p.m. = 12.17 p.m.
Time that the printing started for the slower copier = 12.17 p.m.
(b)
Extra leaflets that the faster copier printed in 50 min
= 50 x 6
= 300
Difference in the time needed to print the leaflets
= 80 - 50
= 30 min
Speed of the slower copier
= 300 ÷ 30
= 10
Number of leaflets printed by the slower copier
= 80 x 10
= 800
Both copiers printed the same number of leaflets.
Number of leaflets printed by the 2 copiers
= 2 x 800
= 1600
Answer(s): (a) 12.17 p.m.; (b) 1600