PSLE One copier took 60 minutes while another took 70 minutes to print the same number of leaflets. The faster copier printed 3 more leaflets per minute than the slower one.
- The slower copier completed the job at 1.44 p.m. At what time was the printing started?
- What was the total number of leaflets printed by the two copiers?
(a)
70 min before 1.44 p.m. = 12.34 p.m.
Time that the printing started for the slower copier = 12.34 p.m.
(b)
Extra leaflets that the faster copier printed in 60 min
= 60 x 3
= 180
Difference in the time needed to print the leaflets
= 70 - 60
= 10 min
Speed of the slower copier
= 180 ÷ 10
= 18
Number of leaflets printed by the slower copier
= 70 x 18
= 1260
Both copiers printed the same number of leaflets.
Number of leaflets printed by the 2 copiers
= 2 x 1260
= 2520
Answer(s): (a) 12.34 p.m.; (b) 2520