PSLE One copier took 60 minutes while another took 80 minutes to print the same number of leaflets. The faster copier printed 3 more leaflets per minute than the slower one.
- The slower copier completed the job at 1.58 p.m. At what time was the printing started?
- What was the total number of leaflets printed by the two copiers?
(a)
80 min before 1.58 p.m. = 12.38 p.m.
Time that the printing started for the slower copier = 12.38 p.m.
(b)
Extra leaflets that the faster copier printed in 60 min
= 60 x 3
= 180
Difference in the time needed to print the leaflets
= 80 - 60
= 20 min
Speed of the slower copier
= 180 ÷ 20
= 9
Number of leaflets printed by the slower copier
= 80 x 9
= 720
Both copiers printed the same number of leaflets.
Number of leaflets printed by the 2 copiers
= 2 x 720
= 1440
Answer(s): (a) 12.38 p.m.; (b) 1440