PSLE One copier took 60 minutes while another took 80 minutes to print the same number of leaflets. The faster copier printed 11 more leaflets per minute than the slower one.
- The slower copier completed the job at 1.53 p.m. At what time was the printing started?
- What was the total number of leaflets printed by the two copiers?
(a)
80 min before 1.53 p.m. = 12.33 p.m.
Time that the printing started for the slower copier = 12.33 p.m.
(b)
Extra leaflets that the faster copier printed in 60 min
= 60 x 11
= 660
Difference in the time needed to print the leaflets
= 80 - 60
= 20 min
Speed of the slower copier
= 660 ÷ 20
= 33
Number of leaflets printed by the slower copier
= 80 x 33
= 2640
Both copiers printed the same number of leaflets.
Number of leaflets printed by the 2 copiers
= 2 x 2640
= 5280
Answer(s): (a) 12.33 p.m.; (b) 5280