PSLEIn the figure, EFGH is a straight line, FHJK is a parallelogram and JG = JK. ∠KEF is a right angle, ∠EKF = 29° and ∠HJG = 13°.
- Find ∠l.
- Find ∠m.
(a)
∠KEF = 90° (Right angle)
∠l
= 90° + 29°
= 119° (Exterior angle of a triangle)
(b)
∠HJK = ∠HFK = 119° (Parallelogram)
∠GJK
= 119° - 13°
= 106°
∠m
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
Answer(s): (a) 119°; (b) 37°