PSLEIn the figure, MNPQ is a straight line, NQRS is a parallelogram and RP = RS. ∠SMN is a right angle, ∠MSN = 24° and ∠QRP = 14°.
- Find ∠t.
- Find ∠u.
(a)
∠SMN = 90° (Right angle)
∠t
= 90° + 24°
= 114° (Exterior angle of a triangle)
(b)
∠QRS = ∠QNS = 114° (Parallelogram)
∠PRS
= 114° - 14°
= 100°
∠u
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
Answer(s): (a) 114°; (b) 40°