PSLEIn the figure, JKLM is a straight line, KMNP is a parallelogram and NL = NP. ∠PJK is a right angle, ∠JPK = 29° and ∠MNL = 13°.
- Find ∠q.
- Find ∠r.
(a)
∠PJK = 90° (Right angle)
∠q
= 90° + 29°
= 119° (Exterior angle of a triangle)
(b)
∠MNP = ∠MKP = 119° (Parallelogram)
∠LNP
= 119° - 13°
= 106°
∠r
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
Answer(s): (a) 119°; (b) 37°