PSLEIn the figure, KLMN is a straight line, LNPQ is a parallelogram and PM = PQ. ∠QKL is a right angle, ∠KQL = 34° and ∠NPM = 18°.
- Find ∠r.
- Find ∠s.
(a)
∠QKL = 90° (Right angle)
∠r
= 90° + 34°
= 124° (Exterior angle of a triangle)
(b)
∠NPQ = ∠NLQ = 124° (Parallelogram)
∠MPQ
= 124° - 18°
= 106°
∠s
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
Answer(s): (a) 124°; (b) 37°