PSLEIn the figure, MNPQ is a straight line, NQRS is a parallelogram and RP = RS. ∠SMN is a right angle, ∠MSN = 34° and ∠QRP = 16°.
- Find ∠t.
- Find ∠u.
(a)
∠SMN = 90° (Right angle)
∠t
= 90° + 34°
= 124° (Exterior angle of a triangle)
(b)
∠QRS = ∠QNS = 124° (Parallelogram)
∠PRS
= 124° - 16°
= 108°
∠u
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
Answer(s): (a) 124°; (b) 36°