PSLEIn the figure, MNPQ is a straight line, NQRS is a parallelogram and RP = RS. ∠SMN is a right angle, ∠MSN = 30° and ∠QRP = 16°.
- Find ∠t.
- Find ∠u.
(a)
∠SMN = 90° (Right angle)
∠t
= 90° + 30°
= 120° (Exterior angle of a triangle)
(b)
∠QRS = ∠QNS = 120° (Parallelogram)
∠PRS
= 120° - 16°
= 104°
∠u
= (180° - 104°) ÷ 2
= 38° (Isosceles triangle)
Answer(s): (a) 120°; (b) 38°