PSLEIn the figure, EFGH is a straight line, FHJK is a parallelogram and JG = JK. ∠KEF is a right angle, ∠EKF = 35° and ∠HJG = 21°.
- Find ∠l.
- Find ∠m.
(a)
∠KEF = 90° (Right angle)
∠l
= 90° + 35°
= 125° (Exterior angle of a triangle)
(b)
∠HJK = ∠HFK = 125° (Parallelogram)
∠GJK
= 125° - 21°
= 104°
∠m
= (180° - 104°) ÷ 2
= 38° (Isosceles triangle)
Answer(s): (a) 125°; (b) 38°