PSLEIn the figure, KLMN is a straight line, LNPQ is a parallelogram and PM = PQ. ∠QKL is a right angle, ∠KQL = 24° and ∠NPM = 20°.
- Find ∠r.
- Find ∠s.
(a)
∠QKL = 90° (Right angle)
∠r
= 90° + 24°
= 114° (Exterior angle of a triangle)
(b)
∠NPQ = ∠NLQ = 114° (Parallelogram)
∠MPQ
= 114° - 20°
= 94°
∠s
= (180° - 94°) ÷ 2
= 43° (Isosceles triangle)
Answer(s): (a) 114°; (b) 43°