PSLEIn the figure, NPQR is a straight line, PRST is a parallelogram and SQ = ST. ∠TNP is a right angle, ∠NTP = 29° and ∠RSQ = 19°.
- Find ∠u.
- Find ∠v.
(a)
∠TNP = 90° (Right angle)
∠u
= 90° + 29°
= 119° (Exterior angle of a triangle)
(b)
∠RST = ∠RPT = 119° (Parallelogram)
∠QST
= 119° - 19°
= 100°
∠v
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
Answer(s): (a) 119°; (b) 40°